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Miner efficiency: the J/TH that decides who survives

Efficiency is input power divided by hashrate — 20 J/TH beats 30 J/TH on the same algorithm. It is the number that decides who stays profitable as difficulty rises and prices fall.

2026-10-19·updated 2026-10-19·3 min·pow.family research#energy#hardware
01

One division, labeled

Efficiency = power ÷ hashrate. A SHA-256 miner drawing 3,000 W at 120 TH/s: 3,000 ÷ 120 = 25 W/TH/s — numerically identical to 25 J/TH (a watt is a joule per second; one terahash per second cancels the seconds). Same math for GPUs: a card at 250 W doing 50 MH/s on its algorithm = 5 W/MH.

Miner-only
3,000 W ÷ 120 TH/s = 25 J/TH
the spec-sheet boundary
With 300 W cooling
3,300 ÷ 120 = 27.5 J/TH
whole-site boundary — label it!
Comparison rule
same algo, same boundary
cross-algorithm J/TH numbers are meaningless
02

Why it decides survival

As difficulty grows or price falls, revenue per terahash drops for everyone equally. The operator whose joules-per-terahash is lowest keeps a positive margin longest. At $0.10/kWh, a 25 J/TH machine spends $0.021/hour per TH/s; a 15 J/TH machine spends $0.0125 — a 40% cost edge that no optimization of anything else can match.

  • Efficiency is not constant: firmware modes, clocks, and temperatures move it — measure at your settings.
  • A lower ratio does not alone prove profitability — purchase price, uptime, and resale still enter the decision.
  • When comparing W/GH vs W/TH convert first: 20 J/TH = 0.02 W/GH.
03

See it live on pow.family

The profitability tool shows your effective $/day per machine at live network numbers — efficiency differences translate 1:1 into the power line.

Sources

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Miner efficiency: the J/TH that decides who survives · pow.family